Question 1103993
{{{8(1.25)^t=8*e^(kt)}}}

{{{1.25^t=e^(kt)}}}

{{{t(ln(1.25))=kt(ln(e))}}}

{{{ln(1.25)=k}}}

{{{k=0.22314}}}


{{{y=8*e^(0.22314t)}}}


NOT decay; but is for exponential growth.  {{{k>0}}}.