Question 98760
{{{(SQRT 4x+1)+3=0}}}
{{{(sqrt4x+1)=-3}}}
{{{(sqrt4x+1)^2=(-3)^2}}}
{{{4x+1=9}}}
{{{4x=9-1}}}
{{{4x=8}}}you subtracted 1 from 9 and got 1
divide 4 into each side: x=2
good work! small mathematical mistake.
Check:
sqrt((4*2)+1)=+3 and -3 (+3 is extraneous for this equation)
Ed