Question 1103779
1. Correct. You add the exponents for x^3*x^3*x^3 while you multiply them in x^(3*3*3)


2. Correct. You should get 1/[ x^(-1/2) ] =  x^(1/2) = sqrt(x) where "sqrt" is shorthand for "square root"


3. Correct. Converting to exponential notation and then adding the exponents gives x^(1/2+1/4) = x^(2/4+1/4) = x^(3/4)


4. <font color=red>Not correct</font>. You forgot to reduce the fraction 4/6 to 2/3. The answer is {{{root(3,x^2)}}} (cube root of x^2)


5. This seems a bit strange. C is hard to decipher. Do you mean the 10th root of all of that? Or just the first portion? You are correct in saying that 1/(x^(-1)) and (x^(1/3)*x^(1/3)*x^(1/3)) are both equal to x^1.