Question 1103760
{{{x=-(y+3)}}}
So then substituting,
{{{(-y-3+6)^2+(y+4)^2=37}}}
{{{(-y+3)^2+(y+4)^2=37}}}
{{{y^2-6y+9+y^2+8y+16=37}}}
{{{2y^2+2y-12=0}}}
{{{y^2+y-6=0}}}
{{{(y+3)(y-2)=0}}}
Two solutions:
{{{y+3=0}}}
{{{y=-3}}}
.
.
{{{y-2=0}}}
{{{y=2}}}
Now use either equation to solve for x.