Question 1103702
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Plant A defective panels + Plant B defective panels = 0.03*Defective panels

0.02*16000               + 0.05*b                   = 0.03*(16000+b)    (counting defective panels)  ====>


320 + 0.05b = 0.03*16000 + 0.03*b

320 + 0.05b = 480 + 0.03*b

0.05b - 0.03b = 480 - 320 = 160

0.02b = 160  ====>  b = {{{160/0.02}}} = {{{1600/2}}} = 8000.


<U>Answer</U>.  Plant B produces 8000 panels.


<U>Check</U>.  0.02*16000 + 0.05*8000 = 720;  0.03*(16000+8000) = 720.   ! Correct !
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This problem (or its TWINS) was solved MANY TIMES in this forum.


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<U>"Two factory plants are making TV panels. Yesterday, Plant A produced" algebra.com</U>