Question 1103753
Let the consecutive even integers be:
{{{ n }}}, {{{ n + 2 }}}, and {{{ n+ 4 }}}
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{{{ 3*( n + 2 ) = n + n + 4 + 6 }}}
{{{ 3n + 6 = 2n + 10 }}}
{{{ n = 4 }}}
and
{{{ n + 2 = 6 }}}
{{{ n + 4 = 8 }}}
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The even integers are 4, 6, and 8
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check:
{{{ 3*( n + 2 ) = 2n + 10 }}}
{{{ 3*6 = 8 + 10 }}}
{{{ 18 = 18 }}}
OK