Question 1103754
Hyperbolas have eccentricities greater than 1.
The vertices are 2 units from the center so {{{a=2}}}
{{{e=c/a}}}
{{{3=c/2}}}
{{{c=6}}}
and
{{{a^2+b^2=c^2}}}
{{{2^2+b^2=6^2}}}
{{{b^2=36-4}}}
{{{b^2=32}}}
So,
{{{highlight_green((x-2)^2/4-y^2/32=1)}}}