Question 1103722
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Of 100 persons in a company, 70 r married, 80 r college graduates, and 60 are both married and college graduates.  
Find the probability that if a person is selected at random from this group, the person will be: 


<pre>
a. Married or not a college graduate....  Their number = n(Married) + n(NOT_college_graduated) - n(Married_AND_college_graduated) = 

                                                       = 70 + (100-80) - 60 = 70 + 20 - 60 = 30.

                                                                    So the probability is  {{{30/100}}} = {{{3/10}}} = 0.3 = 30%.



b. Married and a college graduate....     Their number is 60.          The probability is  {{{60/100}}} = {{{3/5}}} = 0.6 = 60%.



c. Married and not a college graduate.    Their number is 70-60 = 10.  The probability is  {{{10/100}}} = {{{1/10}}} = 0.1 = 10%.
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