Question 1103689
We don't know the total invested.
We know the difference in the two accounts.
We know that the interest for the two accounts is $300
0.08*x+0.06*y=300
We know that the account at 8% has $250 more.
x=250+y
We substitute for x
0.08*(250+y)+0.06*y=300
We multiply out
20+0.08y+0.06*y=300
We combine like terms.
0.14*y=280
Isolate y
y=$2000 at 6%
x=250+y
Calculate x
x=$2250 at 8%
Total invested $2250+$2000=$4250
Now,we know the total invested is: $4250
We check
0.08*2250+0.06*2000=300
180+120=300
300=300
Since this statement is TRUE and neither x nor y is negative all is well.
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