Question 1103535
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Here is a quick way to solve problems like this, if algebra is not required and an answer is to be obtained quickly -- as would be the case if a problem like this were on a competitive timed test.<br>
All 210 tickets $2 each would bring in $420.
The actual total ticket sales was $660, which is $240 more than $420.
Each good ticket costs $3 more than each poor ticket.
The number of good tickets sold was $240/$3 = 80.