Question 1103463
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As tutor ikleyn showed, the problem as you show it is not very interesting, because it has an infinite number of solutions.<br>
So I'm wondering if, perhaps due to a language difficulty, you stated the problem incorrectly.<br>
I suspect the problem was supposed to say that, when the numbers 95, 112, 214, and 231 are divided by a natural number n, the remainders are all the same.<br>
If that is the case, the problem is much easier to solve.<br>
The differences between any two of the given numbers are all multiples of 17, so the answer would be that n is 17.<br>
That is, the numbers 95, 112, 214, and 231, when divided by 17, all leave the same remainder, 10.<br>
Is that by chance what the problem was supposed to be?