Question 1103573
<br>
With the "+1" at the end of the function, the value in the middle of each period has to be +1; that means the correct graph is either A or C.<br>
But the period is pi/3.  The beginnings of the periods for graphs A and C differ by pi, which is an integer multiple of the period, pi/3.<br>
That means BOTH of the graphs A and C are correct; they just show the graph in different periods.<br><br>
Addendum -- for the reader who replied that they can't both be right....<br>
In fact graphs A and C ARE both correct for the given function; if only one graph is to be the correct answer for the problem, then the problem is flawed.<br>
Graph A shows the three points (5pi/12,4), (pi/2,1), and (7pi/12,-2).
Graph C shows the three points (-7pi/12,4), (-pi/2,1), and (-5pi/12,-2).<br>
All 6 of those points are points on the graph of the given function.