Question 1103409
6x² + x = 40
6x² + x - 40 = 0
6x² + 16x - 15x - 40 = 0   {split x into 16x and -15x, they multiply to get 6(-40) and add to get 1}
2x(3x + 8) - 5(3x + 8) = 0   {factored 2x out of first two terms and -5 out of last two terms}
(3x + 8)(2x - 5) = 0  {factored out the common factor, (3x + 8)}
3x + 8 = 0  or  2x - 5 = 0 {set each factor equal to zero}
3x = -8  or  2x = 5  {subtracted 8 and added 5}
x = -8/3 or x = 5/2  {divided by 3 and divided by 2}
<br>For more help like this, visit: <a href = "http://www.algebrahouse.com/" target = "_blank">www.algebrahouse.com</a><br><br><br>