Question 98506
         y1=1/x+3, y2=1/x, and y1+y2=1/15 
Find all the values of x


                1/(x+3)+1/(x) = 1/15

              x+x+3/x(x+3)= 1/15

                15(2x+3)= x(x+3)

                30x+45 = x^2+3x

               x^2+3x-30x-45 = 0

               x^2-27x-45 = 0

     {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

           x = 27 +- sqrt (27^2+180)/2 
     simplify to get the value of x