Question 98657

      Find the measure of an angle whose supplement measures 39 degrees more than twice its complement.

       Let the required angle be  = x degrees

               its supplement will be  = 180-x

               its copliment will be = 90-x

          given supplement = 2(compliment)+39

                     180-x = 2(90-x)+39

                     2x-x = 180-180+39
                        x = 39 degrees