Question 1103214
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The perimeter of a rectangle is 52 feet. 
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p=52
L, length
w, width
p=2w+2L


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The length is 2 feet more than 5 times the width.
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L=5w+2



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Find the dimensions of the rectangle.
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Do that.  All the basic starting data is ready.  Just a couple of substitutions and a few simple algebra steps.