Question 98646


          Solve: [2x-5y] = [1] for y
[ x+3y] [0] 

                  2x-5y = 1...........(1)

                   x+3y = 0...........(2)

           multiply (2) by 2  and subtract (1) and (3)

                       2(x+3y) = 2(0)
                       2x+6y = 0..........(3)

                       2x-5y = 1
                       2x+6y = 0
                       -  -
                     ------------
                       0 -11y = 1
                     ------------

                         y = -1/11

           substituting for y in (2)  we get x+3y = 0
                                                x = -3y = -3(-1/11) = 3/11

         the solution for the eq'ns is x= 3/11  and y = -1/11