Question 98527

      x2 - 12x + 35 > 0
      x^2-7x-5x+35>0

     x(x-7)-5(x-7)>0

      (x-7)(x-5)>0
      (x-7)>0   or x>7

      (x-5)>0   or x>5

     solution is x>7  and x>5