Question 1103065
<br>
P(at least one white marble in 5 draws)
 = 1 - P(no white marbles in 5 draws)
 = 1 - P(every draw is either red or black)<br>
The probability of getting either red or black on each draw is 11/15; the probability of getting red or black on all five draws is (11/15)^5.<br>
So P(at least one white marble in 5 draws) - {{{1 - (11/15)^5 = .7879}}} (to 4 decimal places).