Question 1103122
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The equation you show clearly has a root at x=1.  The other roots are  one irrational and a pair of complex roots.<br>
I'm wondering, though, if the equation was supposed to be x^4-10x^2+9=0.  That equation is easy to solve.<br>
{{{x^4-10x^2+9 = 0}}}
{{{(x^2-9)(x^2-1) = 0}}}
{{{(x+3)(x-3)(x+1)(x-1) = 0}}}<br>
The solutions are -3, 3, -1, and 1.