Question 1103123
.
<pre>
In polar coordinates,  x = {{{r*cos(theta)}}},  y = {{{r*sin(theta)}}}.


So, in polar coordinates the given equation takes the form


{{{6*r*cos(theta) - 7*r*sin(theta)}}} = 5,   or


{{{r*(6cos(theta)-7*sin(theta))}}} = 5,   or


r = {{{5/(6cos(theta)-7*sin(theta))}}}.
</pre>