Question 1103090
y=x^2+5x-3
y-x=2 
y=x+2
x+2=x^2+5x-3
0=x^2+4x-5
0=(x+5)(x-1)
x=-5, 1
when x=-5, y =-3 (-5, -3)
when x=1, y=3 (1, 3)
{{{graph(300,300,-10,10,-10,10,x^2+5x-3,x+2)}}}