Question 1103078
.
<pre>
From the condition, you have the system of 2 equations in 2 unknowns

13*d + 14*p = 233,    (1)    (Anjali' spending)
 5*d +  7*p = 109.    (2)    (Joe' spending)


To solve the system, multiply equation (2) by 2 (both sides). The modified system is

13*d + 14*p = 233,    (3)   
10*d + 14*p = 218.    (4) 


Now subtract eq(4) from eq(3) (both sides).  The terms "14*p" in both equations will cancel each other, and 
you will get a single equation for only one unknown "d" (it is how the Elimination method works):

3d = 233 - 218  = 15  ====>  d =  {{{15/3}}} = 5.


Thus you found that the pot of ivy costs $5.


Then from eq(2),   7p = 109 - 5*5 = 84  and  d = {{{84/7}}} = 12.


<U>Answer</U>.  One daylily costs $12  and  one pot of ivy costs $5.
</pre>


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On solving systems oi two linear equations in two unknowns and related word problems see the lessons

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in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.