Question 1103053
Find the derivative first.
{{{2xdx+2ydy=0}}}
{{{ydy=-xdx}}}
{{{dy/dx=-x/y}}}
{{{-x/y=3/4}}}
{{{-4x=3y}}}
{{{y=-(4/3)x}}}
So then substituting,
{{{x^2+(16/9)x^2=100}}}
{{{(9/9)x^2+(16/9)x^2=100}}}
{{{(25/9)x^2=100}}}
{{{x^2=100(9/25)}}}
{{{x^2=36}}}
So,
{{{x[1]=6}}} and {{{x[2]=-6}}}
Using the formula above,
{{{y[1]=-(4/3)6=-8}}}
and
{{{y[2]=-(4/3)(-6)=8}}}
So its,
(6,-8) and (-6,8)
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*[illustration des7.JPG].
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