Question 1102995
what is the games expected value? 
<pre>
We will subtract the $1 that you play to win, so that
you will win $4 if you roll a 5 and $3 if you roll a
4.

                                 Individual  
Roll   Net win    Probability    Expectation
 1       $0          1/6         $0(1/6)=$0
 2       $0          1/6         $0(1/6)=$0
 3       $0          1/6         $0(1/6)=$0
 4       $3          1/6         $4(1/6)=$3/6
 5       $4          1/6         $5(1/6)=$4/6
 6       $0          1/6         $0(1/6)=$0
 --------------------------------------------
              Total expectation = $(3/6+4/6) = $(7/6) = $1.17
                                          (to nearest penny)
</pre>
B: what does this value mean?<pre>

It means that if you play the game many times, you will lose some 
and win some, but your average winning will be about $1.17 per game.
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 C: What are the odds you will win some money playing this game.
<pre>
There are 6 possible rolls.  On the average out of every 6 you will 
win some money 2 times and win no money 4 times.  So the odds in 
favor of winning some money are 2 to 4, or 2:4, which reduces to
1:2.

Edwin</pre>