Question 1102956
{{{F[1]}}}=({{{100cos(20)}}},{{{100sin(20)}}})
{{{F[1]}}}=({{{93.97}}},{{{34.20}}})
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{{{F[2]}}}=({{{150cos(60)}}},{{{150sin(60)}}})
{{{F[2]}}}=({{{75}}},{{{129.9}}})
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{{{R=F[1]+F[2]}}}
{{{R}}}=({{{93.97+75}}},{{{34.20+129.9}}})
You can then find the magnitude by taking the square root of the sum of the squares of the components.
{{{abs(R)=sqrt(R[x]^2+R[y]^2)}}}
For the angle,
{{{tan(beta)=R[y]/R[x]}}}