Question 1102975
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Multiply the same way you multiply binomials --
e.g., {{{(x-3)(2x+5) = 2x^2+5x-6x-15 = 2x^2-x-15}}}<br>
The difference is that now you will be able to combine more like terms, because {{{i^2=-1}}}.<br>
{{{(2+3i)(3-2i) = 6-4i+9i-6i^2 = 6-4i+9i-6(-1) = 6-4i+9i+6 = 12+5i}}}