Question 1102789
Look at this problem, and remember that parallel lines have the same slope, and the slope of perpendicular lines are negative inverses.
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Find the slope and y intercept of the line, and graph:
2x+3y=18
I got the slope as: -2/3
and the y intercept as: (0,6) is this correct? Also how do I graph that?
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Solve for y, --> slope-intercept form y = mx + b
y = (-2/3)x + 6
m = -2/3 (slope)
b = 6 (y-intercept)
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1) Weite an equation In slope Intercept form of the line hat passes through the given point and Is perpendicular to th graph of the given shaps
(5, 0) ; y + 1 = 2?(x - 3)
A) Y = -1/2x + 5
B) Y = 2x - 5
C) y = 1/2x - 2
D) Y = -1/2x + 5/2 
2) Determine whether the graphs of the given equations are parallel, perpendicular, Or nither
Y = -2x + 3
2x + Y = 7 
A) Parallel
B) Perpendicular
C) Niether
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Find the slope of the 2 graphs.
Y = -2x + 3
2x + Y = 7  ---------- Solve for y
y = -2x + 7
The slope is -2, same as the 1st equation.
---> parallel.
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3) Determine whether the graphs of the given equations are parallel, Perpendicular, Or niether
Y = x + 11
Y = -x - 2
A) Parallel
B) Perpendicular
C) Niether
The slope of the 1st eqn is +1
The slope of the 2nd eqn is -1
They are negative reciprocals ----> perpendicular.
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4) Determine whether the graphs of the given equations are parallel, Perpendicular Or nither
Y = -2x + 3
2x + 4y = 0 
A) Parallel
B) Perpendicular
C) Niether 
Solve the 2nd eqn for y.  then the slope is the coefficient of x.
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5) Determine whether the given equations are parallel, Perpendicular, Or Niether
Y = 4x - 2
-x + 4y = 0
A) Parallel
B) Perpendicuar
C Niether
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Solve the 2nd eqn for y.  then the slope is the coefficient of x.
If the slopes are equal, they're parallel.
If the product of the 2 slopes = -1, they're perpendicular.
otherwise, neither.