Question 1102780
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There are 100 centimeters in a meter and 1000 meters in a kilometer, so there are 100,000 centimeters in a kilometer.


The diameter of the tire is 75 cm, so the circumference of the tire is *[tex \Large 75\pi] centimeters.


Hence the number of revolutions of the tire when the car has gone 1 kilometer is *[tex \Large\ \frac{100,000}{75\pi}].


Since the car is traveling at 110 km/hr, the number of revolutions in an hour is  *[tex \Large\ \frac{100,000}{75\pi}\ *\ 110]


But there are 60 times 60 or 3600 seconds in an hour, so the number of revolutions per second is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{ \frac{100,000}{75\pi}\ *\ 110}{3600}]


Since there are *[tex \Large 2\pi] radians in 1 revolution, the radian measure of the angle traversed by a point on the tire not located at the center of the tire would be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{ \frac{100,000}{75\pi}\ *\ 110}{3600}\right)*2\pi]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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