Question 1102681
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{{{sqrt(x+6) + sqrt(2-x) =4}}}<br>
Not a very helpful solution from the other tutor.  If he is in fact doing what you asked him to ("tell me the first step or two"), then his response is useless, because he doesn't say anything about HOW to get rid of the radicals.<br>
In fact, the way you get rid of the radicals is by squaring both sides, which he seems to give as his second step....<br>
In fact you are going to have to square both sides of the equation to get rid of the radicals.  But because the equation contains two radicals, you are going to have to square both sides TWICE -- one time to get rid of each of the radicals.<br>
It is usually easiest, if the two radicals are on the same side of the given equation, to move one of them, so that the two radicals are on different sides of the equation:
{{{sqrt(x+6) = 4 - sqrt(2-x)}}}<br>
So now square both sides, remembering all the terms when you square the right side:<br>
{{{x+6 = 16 - 8*sqrt(2-x) + (2-x)}}}<br>
Since you asked for the first step or two, I will stop there.<br>
Simplify this equation, get the remaining radical by itself on one side of the equation, and square both sides again....<br>
When you do all the rest of the work, you should find a single solution: x = -2.