Question 1102656
This is only a start -  not the whole solution.


Recognize that whatever you find,  {{{x<>-4}}}.


{{{6/(x+4)-4/(3x+12)+1<=0}}}

Common denominator {{{3(x+4)}}};

{{{(3/3)(6/(x+4))-4/(3x+12)+(3(x+4))/(3(x+4))<=0}}}

{{{18/(3x+12)-4/(3x+12)+(3x+12)/(3x+12)<=0}}}



---------------Below here is faulty because accounting for both numerator AND denominator and critical x values must be done------------------------------
{{{18-4+3x+12<=0}}}
{{{3x+12+18-4<=0}}}
{{{3x+26<=0}}}

recheck for any mistakes, and continue...