Question 1102614
{{{ln(2*pi)-ln(g^(1/2))=c}}}

{{{ln(2*pi)-c=ln(g^(1/2))}}}

{{{(1/2)ln(g)=ln(2*pi)-c}}}

{{{ln(g)=2*ln(2*pi)-2c}}}

{{{highlight(g=e^(2*ln(2pi)-2c))}}}