Question 98596
4X^2+3X-5=0
USING THE QUADRATIC EQUATION:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} WE GET:
X=(-3+-SQRT[3^2-4*4*-5])/2*4
X=(-3+-SQRT[9+80])/8
X=(-3+-SQRT89)/8
X=(-3+-9.434)/8
X=(-3+9.434)/8
X=6.343/8
X=.8 ANSWER.
X=(-3-9.434)/8
X=-12.434/8
X=-1.55 ANSWER.