Question 1102579
<pre>
Here it is with a little more detail:

{{{(2x^6y^(-2))^4}}}

Give the coefficient 2 a visible exponent of 1

{{{(2^1x^6y^(-2))^4}}}

Multiply each of the three exponents inside the 
parentheses by the exponent 4 just outside the 
parentheses and remove the parentheses:

{{{2^4x^24y^(-8)}}}

To make the negative exponent positive, move it
to a denominator down below the other factors:

{{{2^4x^24/y^8}}}

2<sup>4</sup> means (2)(2)(2)(2) = 16

{{{16x^24/y^8}}}

Edwin</pre>