Question 1102502
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This problem is solved in four easy steps:


<pre>
    1.  The bottom area of the open box = {{{Volume/Height}}} = {{{1536/6}}} = 256 cm^2.


    2.  The side measure of the box bottom = {{{sqrt(256)}}} = 16 cm.


    3.  The side dimension of the original square piece of tin is 16 + 2*6 = 28 cm.


    4.  The area of the original piece of tin is 28^2 = 784 cm^2.
</pre>

<U>Answer</U>.  The area of the original piece of tin is 784 cm^2.



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Be aware !!  &nbsp;&nbsp;The approach and the solution by @josgarithmetic are &nbsp;&nbsp;<U>I N A D E Q U A T E  &nbsp;&nbsp;AND&nbsp;&nbsp;  &nbsp;&nbsp;I R R E L E V A N T</U> !!