Question 1102389
f(x) = log(2x+3)
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assume the log base is 10
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range is all real numbers
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domain is x > -3/2
Note negative logarithms are not defined so x can not be < -3/2
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since log base 10 of 1 is 0, the x intercept is (-1,0)
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y intercept is when x = 0, this gives us (0, log base 10 of 3)
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Here is solution for x intercept (-1, 0)
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log(10) (2x+3) = log (2x+3) / log (10)
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log (2x+3) / log (10) = 0
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log (2x+3) = 0
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remove log by taking exponent of both sides of =
"
2x + 3 = 1
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2x = -2
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x = -1
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