Question 1102270
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Here is an alternative method for solving these "working together" problems that I find many students prefer to the standard algebraic method shown by the other tutors.<br>
One hose takes 40 hours to fill the pool alone; another takes 60 hours.
Imagine you have several of these pools.
The least common multiple of 40 and 60 is 120.
In 120 hours the first hose could fill 3 pools and the second hose could fill 2 pools.
So in 120 hours the two hoses together could fill 5 pools.
But at that rate the two together could fill the one pool in 120/5 = 24 hours.