Question 1102263
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<U>1 - Physics style solution</U>


<pre>
Time to catch = {{{(2*16)/(30-2)}}} = {{{32/28}}} hours = {{{1}}}{{{4/28}}} hours = {{{1}}}{{{1/7}}} hours.


<U>Explanations</U>:


2*16 = 32 miles in the numerator is the "head start distance".

(30-2) = 28 miles per hour in the denominator is their relative speed,

         which is EXACTLY THE RATE of decreasing the distance between them.
</pre>


<U>2 - Algebra style solution</U>


<pre>
30*t = 2*(t+16).        <<<<----====  This equation says that they cover the same distance, but for different time.


Solve for t, which is time counted after the tiger started.


After completing this simple solution you will get the same answer.
</pre>


See the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- - <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- - <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- - <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

in this site.



Everything is/was explained there.


You will find TONS of similar solved problems there.



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@josgarithmetic took very inadequate approach to solve the problem.


NEVER USE SUCH approach in problems like this.