Question 1102263
Not the only method, but

<pre>
                SPEED      TIME           DISTANCE
FAST CAT          30         d/30            d
SLOW CAT           2         d/2             d
Difference                 16
</pre>

Find d, first and use for finding {{{d/30}}}.

{{{highlight_green(d/2-d/30=16)}}}

{{{30(d/2-d/30)=30*16}}}

{{{15d-d=30*16}}}

{{{14d=30*16}}}

{{{7d=30*8}}}

{{{d=240/7}}}

{{{d=34.2857*miles}}}, or  {{{34&2/7}}}{{{miles}}}



TIME FOR THE TIGER
{{{d/30}}}


{{{(240/7)(1/30)}}}


{{{highlight_green(1.1429*hours)}}}
-
1 hour 9 minutes