Question 1102243
 Determine the direction angle for the following vector: 
v = -8i+8 sqrt(3) j 
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Note that v is in QII where the tan is negative::
theta = arctran[(8sqrt(3)/-8] = arctran[-sqrt(3)] = 180-60 = 120 degrees
or (2/3)pi radians
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Cheers,
Stan H.
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