Question 1102195
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Since the number of 1R coins is 5 times the number of 2R coins, imagine grouping the coins into groups of 5 1R coins and 1 2R coin.
The value of each of those groups is 5(1R)+1(2R) = 5R+2R = 7R.
If the total value of all the coins is 70R, then there must be 70/7 = 10 of those groups.
Since each group contains 5 1R coins and 1 2R coin, the number of 1R coins is 10*5 = 50 and the number of 2R coins is 10+1 = 10.