Question 98495
4x-3y=10
we find the slope by converting the equation into the form: y=mx+b where m=slope
subtract 4x from each side. -3y=-4x+10
divide -3 into each side. y=(4/3)x-10/3
so m=4/3
by definition the slope of the line perpendicular to this line is the negative reciprocal of its slope. So {{{m=-1/m[1]=-3/4}}}.
we use the point-slope form to find the formula of the line.
{{{y-y[1]=m(x-x[1]) }}}
 for (8,-3): y-(-3)=-3/4(x-8)
y-(-3)=-3x/4+3/4*8
y+3=-.75x+6
subtract 3 from each side. y=-.75x+3
Ed
{{{graph(500,500,-10,10,-10,10,1.25x-10/3,-.75x+3)}}}