Question 1101859
here is the problem worked out for 14 tablets and 3%

In order for there to be no defects then all 14 of the test tablets must be good so 
 
P(no defects out of 14) = 0.9714 ~ 0.6528  
 
If there is 1 tablet that is bad then it can be any one of the 14 tablets (this can happen in 14 different ways), times the probability that 1 tablet is bad and 13 are good, so 
 
P(1 defect out of 14) = 14*0.03*0.9713 ~ 0.2827
 
The probability that either of these cases happen is the sum of the individual probabilities which is 
 
P(shipment accepted) = 0.6528 + 0.2827 = 0.9355