Question 1101954
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The word contains 8 letters;  of them,  the "A" repeats twice, and "R" repeats twice, too.


Thus the number of distinguishable arrangements of the letters is  {{{8!/(2!*2!)}}} = 10080.


First   2!  in the denominator stands to account for repeated  "A".
 

Second  2! in the denominator stands to account for repeated  "R".
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