Question 1101907
Part A only.
You could use a scientific or graphing calculator for help.


Hydronium concentration,  0.00204 M


{{{pH=-log((0.00204))}}}

{{{-log((2.04*10^(-3)))}}}

{{{-(log((2.04))+log((10^(-3))))}}}

{{{-log((2.04))+3*1}}}

{{{-0.30963+3}}}

{{{highlight(pH=2.69)}}}



For part B, think:  Does your answer make sense to you?
Given pH=3.2, what does this mean?

{{{3.2=-log((C))}}}
and your base is 10 for Common Logs
and C is your molarity for hydronium ion concentration.


From that, {{{log((C))=-3.2}}}

{{{10^(-3.2)=C}}}

which you could use your calculator to get the decimal value for C.