Question 1101847
Let A be the event that at least two justices have the same birthday.

P(A) = 1 - P(A')
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P(A') = (364/365)*(363/365)*(362/365)*(361/365)*(360/365)*(359/365)*(358/365)*(357/365)
P(A') = (364*363*362*361*360*359*358*357)/(365^8)
P(A') = 0.9053762
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P(A) = 1-0.9053762 = 0.0946238, rounded to 4 decimal places: <b>0.0946</b>