Question 1101735
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The first tutor had an error in his algebra; the second tutor didn't read the problem correctly.  There is a solution to your problem.<br>
Let the number of quarters be q;
then the number of nickels is q+8.
Then, since the total number of coins is 66, the number of dimes is {{{66-(q+(q+8)) = 58-2q}}}<br>
We are told the value of the dimes is $3.20 less than the value of the quarters.  Writing the equation in cents instead of dollars:
{{{10(58-2q) = 25q - 320}}}
{{{580-20q = 25q-320}}}
{{{900 = 45q}}}
{{{q = 20}}}
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The number of quarters is 20; so the number of nickels is 28; so the number of dimes is 18.