Question 1101595
Let the 3 consecutive integers be
{{{ n }}}, {{{ n+1 }}}, and {{{ n + 2 }}}
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{{{ n + n + 1 + n + 2 = 5n - ( n+2 ) }}}
{{{ 3n + 3 = 5n - n - 2 }}}
{{{ 3n = 4n - 5 }}}
{{{ n = 5 }}}
and
{{{ n + 1 = 6 }}}
{{{ n + 2 = 7 }}}
The consecutive integers are 5, 6, and 7
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check:
{{{ n + n + 1 + n + 2 = 5n - ( n+2 ) }}}
{{{ 5 + 6 + 7 = 5*5 - 7 }}}
{{{ 18 = 25 - 7 }}}
{{{ 18 = 18 }}}
OK