Question 1101547
 makau made a journey of 700km partly by train and partly by bus.
 he started his journey at 8.00am by train which travelled at 50km/hr.
 after alighting from the train he took a lunch break of 30 minutes.
 he then continued his journey by bus which travelled at 75km/hr.
 the whole journey took eleven and a quarter hours.
:
 a) i) determine the distance travelled by bus
let b = distance traveled by bus
the whole journey is 700 km, therefore
(700-b) = distance traveled by train
subtract the lunch break from the total time: 11.25 -.5 = 10.75 hrs travel time
:
Write a time equation, time = dist/speed
  bus time + train time = 10.75 hrs
{{{b/75}}} + {{{((700-b))/50}}} = 10.75
get rid of the denominators, multiply equation by 150, cancel and you have
2b + 3(700-b) = 150 * 10.75
2b + 2100 - 3b = 1612.5
2b - 3b = 1612.5 - 2100
-b = -487.5
b = 487.5 km by bus
then
700 - 487.5 = 212.5 km by train
 ii) the time makau started travelling by bus.
{{{487.5/75}}} = 6.5 hrs
Find the arrival time: 8:00 + 11:15 = 19:15 or 7:15 PM
7:15 - 6:30 = 12:45 PM he got on the bus