Question 1101467
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Find the largest angle in a triangle with sides 6.0 cm, 7.0 cm, and 8.0 cm. 
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The angle opposite the largest side is the largest angle.


a^2 = b^2 + c^2 - 2bc*Cos(A)


Cos(A) = [b^2+c^2-a^2]/(2bc)


Cos(A) = (6^2+7^2-8^2)/(2*6*7) = {{{1/4}}}.


A = arccos(1/4) =   75.56 degrees (approximately).
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